Help in C Arithmetics

[uaecasher]

Hello,

i have written this code:



#include <stdio.h>
int main (void)
{

int a = 15;
int b = 35;


printf("a / b * b = %i\n", a / b * b);


}




the result i get is zero, but it should be 15, why I'm getting a 0

thanks

[Wes]

You need to think about the order this is being evaluated, see: http://www.difranco.net/cop2220/op-prec.htm

a / b * b becomes (a / b) * b

where:
a = 15;
b = 35;

(15/35)*35
0*35

Remember these are integers so 15/35 will be 0. If you want to get the fractional part you'll need to use floats or doubles.

[EMT]

Use parenthesis in your expressions to make it safe.:

[Sander]

Use parenthesis in your expressions to make it safe.:

That wouldn't help in this case - it's the integer division that's the problem here.

[gnasher729]

Hello,

i have written this code:



#include <stdio.h>
int main (void)
{

int a = 15;
int b = 35;


printf("a / b * b = %i\n", a / b * b);


}




the result i get is zero, but it should be 15, why I'm getting a 0

thanks

It should be zero. Buy a C book for beginners.