View Full Version : Problem in php ajax post value.

Dec 6, 2010, 07:40 PM
I want to post value from index.php, then get the value by self without refresh the page. one botton with two values, I want explode them and finally get $namea and $nameb. then use them in other php part.
but when I use echo $name, in the source code, I can see <div id='msg'></div>(html tag), this is not a pure value, so I tried to use strip_tags, but the value lost. it seems the left the ajax pointed div tag, the value also gone.


<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<script language="javascript">
function saveUserInfo() {
var msg = document.getElementById("msg");
var f = document.user_info;
var userName = f.user_name.value;
var url = "value.php";
var postStr = "user_name="+ userName;
var ajax = false;

if(window.XMLHttpRequest) {
ajax = new XMLHttpRequest();
if (ajax.overrideMimeType) {
} else if (window.ActiveXObject) {
try {
ajax = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try {
ajax = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e) {

if (!ajax) {
return false;

ajax.open("POST", url, true);
ajax.onreadystatechange = function() {
if (ajax.readyState == 4 && ajax.status == 200) {
var myPhpVariable = ajax.responseText;
msg.innerHTML = myPhpVariable;
// myPhpVariable is now a variable which you can use
alert( myPhpVariable );
echo $name="<div id='msg'></div>";
$name2 = explode("|",$name1);
<form name="user_info" id="user_info" method="post">
<input name="user_name" type="hidden" value="abc|def" /><br />
<input type="button" value="abc|def" onClick="saveUserInfo()">


echo $_POST["user_name"];

Dec 7, 2010, 06:45 AM
This isn't good code here,
echo $name="<div id='msg'></div>";