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macOS convert int to char in c
- Thread starter widgetman
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Do you mean an Interger or an int?
And do you need to save the string or can you just printf() it...?
And do you need to save the string or can you just printf() it...?
Use sprintf... I believe the syntax goes something like this:
char buffer[100];
int myInteger = 10;
sprintf(buffer, "%i", myInteger);
buffer is a character array, the stuff in the quotes is your string formatting, and myInteger is the integer to format as a string.
So... if you did the following code:
cout << buffer << endl;
You'd see:
10
char buffer[100];
int myInteger = 10;
sprintf(buffer, "%i", myInteger);
buffer is a character array, the stuff in the quotes is your string formatting, and myInteger is the integer to format as a string.
So... if you did the following code:
cout << buffer << endl;
You'd see:
10
Found this on the net:widgetman said:
Code:
char * intToString(int num)
{
int i=0;
int j=0;
int k=0;
int ones=0;
char temp[5]; //5=num digits in 32676
char ans[5];
while (num!=0)
{
ones=num%10; //get current ones digit
temp[i]=(char)(ones+48); //48=(int)'0';
num=num/10; //remove current ones digit
i++; //length of number
}
for(j=i-1;j>=0;j--)
{
ans[k]=temp[j]; //reorder string correctly
k++;
}
ans[i]='\0'; //add null char for end of string
return (char *)ans;
}
)
Would this work, using the standard C library?
Code:
int myint ;
char mystringbuffer[20] ;
snprintf(mystringbuffer,sizeof(mystringbuffer),"%d",myint) ;Mitthrawnuruodo said:Found this on the net:..but there is a method, I just got to remember what it was called... (it's been a couple of years since I programmed much in c...Code:char * intToString(int num) { int i=0; int j=0; int k=0; int ones=0; char temp[5]; //5=num digits in 32676 char ans[5]; while (num!=0) { ones=num%10; //get current ones digit temp[i]=(char)(ones+48); //48=(int)'0'; num=num/10; //remove current ones digit i++; //length of number } for(j=i-1;j>=0;j--) { ans[k]=temp[j]; //reorder string correctly k++; } ans[i]='\0'; //add null char for end of string return (char *)ans; }
NOOOOOOOOOOOOO!!!!!!!!!!!!!! This is way too complicated.
I'm so stupid (forgive me, its 2:30AM, here...) EDIT: And I see this has been pointed out already... by several posters...
You can of course use sprintf()...
And when you have it in a char buffer, getting it into a string should be easy, right...
Edit2: Funny that it 20 digits seems to be enough, right Dr. Q...?
You can of course use sprintf()...
Code:
int num;
char myBuf[20];
sprintf(myBuf, "%i\0", num);And when you have it in a char buffer, getting it into a string should be easy, right...
Edit2: Funny that it 20 digits seems to be enough, right Dr. Q...?
Mitthrawnuruodo said:I'm so stupid (forgive me, its 2:30AM, here...) EDIT: And I see this has been pointed out already...
You can of course use sprintf()...
Code:int num; char myBuf[20]; sprintf(myBuf, "%i\0", num);
And when you have it in a char buffer, getting it into a string should be easy, right...
You don't need the \0 in the format... sprintf automatically adds the null termination...
BTW... not stupid... just took the long way around.
Yes, I know sprintf() does this for me, but if I've learned one thing from my C/C++ days, it's that it never hurts to terminate the strings manually, too...hcuar said:You don't need the \0 in the format... sprintf automatically adds the null termination...
BTW... not stupid... just took the long way around.
And the real irony, is that i suggested printf() in my first respons, without remembering sprintf()... that's really embarrassing...