Dzung

Jan 31, 2012, 11:09 PM

can someone please help simplify the below two Boolean Algebra expressions.

Y=(AB)+(~AC)+(BC)

Z= (AB)+(~AC)

thanks

Y=(AB)+(~AC)+(BC)

Z= (AB)+(~AC)

thanks

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Dzung

Jan 31, 2012, 11:09 PM

can someone please help simplify the below two Boolean Algebra expressions.

Y=(AB)+(~AC)+(BC)

Z= (AB)+(~AC)

thanks

Y=(AB)+(~AC)+(BC)

Z= (AB)+(~AC)

thanks

chown33

Jan 31, 2012, 11:23 PM

google search terms: wolfram alpha boolean algebra (http://www.wolframalpha.com/examples/BooleanAlgebra.html)

lee1210

Jan 31, 2012, 11:37 PM

Seems like homework. The first reduces to the second. The second seems done to me.

-Lee

-Lee

gnasher729

Feb 1, 2012, 02:46 AM

can someone please help simplify the below two Boolean Algebra expressions.

Y=(AB)+(~AC)+(BC)

Z= (AB)+(~AC)

Take the first one, and then express it in words. Please post the result - feedback is very much appreciated. ("Thank you for your help" is no feedback). While lee's answer is completely correct, when I did homework it wouldn't have been accepted (because there is no evidence how you got to the answer).

If AB isn't true, and ~A isn't true, what can you say about B and why?

Y=(AB)+(~AC)+(BC)

Z= (AB)+(~AC)

Take the first one, and then express it in words. Please post the result - feedback is very much appreciated. ("Thank you for your help" is no feedback). While lee's answer is completely correct, when I did homework it wouldn't have been accepted (because there is no evidence how you got to the answer).

If AB isn't true, and ~A isn't true, what can you say about B and why?