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Forgotten two digits of an encrypted disk image's passphrase!

J@ffa

J@ffa

macrumors 6502a
Original poster
Stupidly, I set up an encrypted sparse disk image and used OS X's password assistant thingy to think up a password for it. I'd forgotten it, but I found the piece of paper where I scribbled a reminder. It basically goes like this;

longbunchofwordsgoeshere####anotherfewlongwordshere

I've forgotten the second two numbers of the ## in the middle. Is there anything I can use to, I guess, bruteforce just those two numbers without having to sit there typing all the possible combinations? Thanks!
 
J@ffa said:
Stupidly, I set up an encrypted sparse disk image and used OS X's password assistant thingy to think up a password for it. I'd forgotten it, but I found the piece of paper where I scribbled a reminder. It basically goes like this;

longbunchofwordsgoeshere####anotherfewlongwordshere

I've forgotten the second two numbers of the ## in the middle. Is there anything I can use to, I guess, bruteforce just those two numbers without having to sit there typing all the possible combinations? Thanks!
Click to expand...

Isnt there just 100 possible combinations, 00-99? How long would that take to do?
 
notsofatjames said:
cant automater do it ? I've never found a use for it yet, but this sounds like the sort of thing its for... cracking passwords.
Click to expand...

lol, it sounds easy enough but automator actually can only do things that its been trained to do.. useless for me but I love the cute icon.
 
Well there is no easy way. But here is one way you can at lest get it.

Copy and past the code below. Tabbing is very important.
replace longbuchofwordsgoeshere and anotherfewlongwordshere with the two parts of your phrase.

Code: 
#!/usr/bin/python

FirstPart="longbunchofwordsgoeshere"
SecondPart="anotherfewlongwordshere"
ValidRange = ["(", ")", "*", "+", ",", "-", ".", "/", "0", "1", "2", "3", "4", "5", "6", "7", "8", "9", ":", ";", "<", "=", ">", "?", "@", "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z", "[", "\\", "]", "^", "_", "`", "a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z", "{", "|", "}", "~"]
File = open("FindPossiblecCmbination.txt","a")
cnt = 0
for i in ValidRange:
	for j in ValidRange:
		File.write(FirstPart+i+j+SecondPart+"\n")
	cnt=cnt+1
	print "%s%%"%(float(cnt)/float(len(ValidRange))*100.0) 

File.close()

save the file in raw text mode as in your home directory as FindKey.py
go into the terminal app Applications->Utilities->Terminal

Type
Code: 
chmod 755 FindKey.py
./FindKey.py

Use text edit and open up the file called FindPossiblecCmbination.txt located in your home directory Open that up and Cut and Past each combination.
 
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