PDA

View Full Version : Unauthorized entry in iTunes Connect!




JamesFoote
Aug 30, 2008, 11:49 PM
Hey there, I just paid my 99 dollars as an individual but now, when I try to log onto iTunes Connect, it says I am not allowed!!

Do I just have to wait a few days??



ghayenga
Aug 31, 2008, 12:32 PM
Hey there, I just paid my 99 dollars as an individual but now, when I try to log onto iTunes Connect, it says I am not allowed!!

Do I just have to wait a few days??

Yes, it's not immediate.

ploppy
Aug 31, 2008, 02:22 PM
Hey there, I just paid my 99 dollars as an individual but now, when I try to log onto iTunes Connect, it says I am not allowed!!

Do I just have to wait a few days??

No, it's supposed to be immediate. Give them a call.

Encryptic
Aug 31, 2008, 07:46 PM
No, it's supposed to be immediate. Give them a call.

Not true, you have to activate your key via the email you receive before your account becomes active and able to enter the program portal.

ploppy
Aug 31, 2008, 08:15 PM
Not true, you have to activate your key via the email you receive before your account becomes active and able to enter the program portal.

Oops, I meant that it should be immediate as you activate your membership.

DreamPod
Sep 2, 2008, 09:40 PM
Wait, you *just* paid your $99 and are already trying to get into iTunes Connect? Is your app working perfectly on hardware then? iTunes Connect is only for submitting apps and managing submitted apps, not for testing on hardware. Getting access to the special section of the website (where you can get all the stuff for testing apps on hardware) is immediate upon entering in the code you get in the email, but I'm not sure about iTunes Connect.

caveman_uk
Sep 3, 2008, 03:19 AM
iTunes Connect is only for submitting apps and managing submitted apps, not for testing on hardware.
Not entirely true. It's also where the contracts are handled. If you plan on selling your app you need to sort out contracts with Apple (and deal with the tax issues). I'd recommend doing this sooner rather than later.