iOS question concerning NSLog and the output in console

U

ulquiorra

macrumors member

Original poster

• Sep 11, 2009

• #1

I have question concerning a function I created.
I would like to show the timeinterval in my console output.

Code:

    -(void)MyTimeInterval:(id)sender
    {
    	NSDate *then = [NSDate date];
    	 
    	NSDate *now = [NSDate date];
    	
    	NSTimeInterval interval = [now timeIntervalSinceDate:then];
    	
    	NSLog(@"let me see the timeinterval between now and then %d", interval);
    }

Does anyone have an idea what I should use to see the interval in the console output.
It's not %d... I don't think I'm doing something wrong here in my function ( could be wrong of course ) , so I'm guessing it must be %d.

 

U

ulquiorra

macrumors member

Original poster

• Sep 11, 2009

• #2

I'm going to answer my own question here and not delete it maybe it can be usefull to someone else

it's %f 😉

 

Darkroom

Guest

• Sep 11, 2009

• #3

NSTimeInterval is not an integer, it's an object.

Code:

NSDate *dateObject = [NSDate date];
NSLog(@"[B]%@[/B]", dateObject);

int dateInteger = 5;
NSLog(@"%i", dateInteger);

float dateFloat = 4.84682;
NSLog(@"%.2f", dateFloat);

 

H

HerQ

macrumors newbie

• Sep 11, 2009

• #4

Darkroom said:

NSTimeInterval is not an integer, it's an object.

Code:

NSDate *dateObject = [NSDate date];
NSLog(@"[B]%@[/B]", dateObject);

int dateInteger = 5;
NSLog(@"%i", dateInteger);

float dateFloat = 4.84682;
NSLog(@"%.2f", dateFloat);

Click to expand...

NSTimeInterval is _not_ an object, it simply is a typedef of double.

 

Darkroom

Guest

• Sep 11, 2009

• #5

HerQ said:

NSTimeInterval is _not_ an object, it simply is a typedef of double.

Click to expand...

woops, meant to write NSDate in line with my example... 😱

[edit] and that still wouldn't have answered the OP's question, which leads me to believe it's time for the first morning coffee