macOS cout << complex weird problem!

mkii said:

Hi,
The following segment:

Code:

#include <iostream>
#include <complex>

int main (int argc, char * const argv[]) 
{
    std::complex<double> a(1.,1.);
    std::cout << "a = "<< a << "\n";
    return 0;
}

using Xcode 3.2 (the project setting is 'Command Line tool') on OSX 10.6.8 compiles fine and produces the following output:

a = (

when of course it should produce:

a = (1.,1.)

Yes, I can display the real and imaginary parts using a.real(), a.imag() but the above should work.

Any ideas why Xcode / OSX has this weird behaviour? Has anyone else seen this, any suggestions?
Cheers,
m

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g++ main.cc -o cout

#include <iostream>
#include <complex>

int main (int argc, char * const argv[]) 
{
    std::complex<double> a(1.,1.);
    std::cout << "a = "<< a << "\n";
    std::cout.flush();
    return 0;
}

mkii said:

Thanks drsoong,

I tried

std::cout.flush();

but it made no difference.

Like you say it is almost certainly an Xcode problem, I would use a terminal and g++ but it is a largish project so Xcode is useful. For portability reasons I hope to get to the bottom of it rather than writing
cout << "a=" << a.real() << a.imag()
everywhere.
mk ii

Click to expand...

drsoong said:

You could try to force a "flush" of the output buffer, using std::cout.flush(); after you print the complex number, i.e.

-DrSoong

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