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 Jan 31, 2012, 11:09 PM #1 Dzung macrumors newbie   Join Date: Jan 2012 Boolean Algebra can someone please help simplify the below two Boolean Algebra expressions. Y=(AB)+(~AC)+(BC) Z= (AB)+(~AC) thanks 0
 Jan 31, 2012, 11:23 PM #2 chown33 macrumors 601   Join Date: Aug 2009 google search terms: wolfram alpha boolean algebra 0
 Jan 31, 2012, 11:37 PM #3 lee1210 macrumors 68040     Join Date: Jan 2005 Location: Seattle, WA Seems like homework. The first reduces to the second. The second seems done to me. -Lee 0
Feb 1, 2012, 02:46 AM   #4
gnasher729
macrumors G4

Join Date: Nov 2005
Quote:
 Originally Posted by Dzung can someone please help simplify the below two Boolean Algebra expressions. Y=(AB)+(~AC)+(BC) Z= (AB)+(~AC)
Take the first one, and then express it in words. Please post the result - feedback is very much appreciated. ("Thank you for your help" is no feedback). While lee's answer is completely correct, when I did homework it wouldn't have been accepted (because there is no evidence how you got to the answer).

If AB isn't true, and ~A isn't true, what can you say about B and why?
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