Can someone explain to me exactly what is going on here?

Discussion in 'Mac Programming' started by chrono1081, Jul 8, 2009.

  1. macrumors 604


    Jan 26, 2008
    Isla Nublar
    I wanted to check the apple documentation but apples site doesn't play well with my work proxy : /

    I'm coming from C++ and learning Objective-C and I was working through an exercise in a book and I realize that a line in the exercise doesn't do what I thought it did. Here is the program: (I'll just write the important parts)

    First here is part of the fraction class implementation file, notice it creates a memory leak.

    -(Fraction *) add: (Fraction *) f
    Fraction *result = [[Fraction alloc] init];
    //other stuff here
    return result;
    Now here is part of main.

    //At the top of main we have this here creating a new fraction object
    Fraction *aFraction = [[Fraction alloc] init];
    Fraction *sum = [[Fraction alloc] init], *sum2;
    //stuff here, skipping down to the for loop
    for (i = 1; i <= n; ++i)
    [aFraction setTo: 1 over: pow2];
    sum2 = [sum add: aFraction];
    [sum release];
    //Here it is....
    sum = sum2;
    I thought that when I released it I would be destroying the object but right underneath the release of sum it gets used again without being reallocated. Am all I doing is clearing the data stored in sum? Would I need to use some type of dealloc keyword to destroy the object?
  2. macrumors regular

    Nov 24, 2006
    The Netherlands
    Not really... You return a pointer to the allocated memory, so you are free to release the memory later. It is not a real leak. (you didn't lose the pointer to the memory)

    When you alloc an object it has a retain count of 1 ... You can increase or decrease this retain count by using 'retain' or 'release'. Now, if your object receives a release when it has a retain count of 1 then it is assumed no other code is interested in the object, so the memory for the object can be de-allocated.

    That is what is happening here.

    1: sum2 is just a pointer to a fraction.
    2: add: returns a pointer to an allocated fraction.
    3: sum2 now points to the allocated fraction having a retain count of 1.
    4: You release sum (retain now 0), thus deallocating the memory originally used by sum, leaving you with a usable/free pointer which you can point to any fraction again.
    5: You let sum point to the same fraction as sum2 is pointing to.
  3. thread starter macrumors 604


    Jan 26, 2008
    Isla Nublar
    Thank you for the clarification :)

    It didn't hit me looking at the exercise that the pointer was never lost. It all makes sense now :)

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