Hi! I want my app to open url in Safari and to login. I know how to just open URL: Code: UIApplication *app = [UIApplication sharedApplication]; [app openURL:[[NSURL alloc] initWithString:@"http://www.somedomain.net"]]; But there is a login form on that site. Here is it's code: Code: <form action="http://www.somedomain.net/login.php" method="post"> ... <td width="68%"><input name="username" class="formlogin" size="23" type="text" /></td> <td width="10%"> </td> </tr> <tr> <td>Password:</td> <td><input name="pass" class="formlogin" size="23" type="password" /></td> it looks like I have to POST params to http://www.somedomain.net/login.php Well, I know how to POST Code: NSString *myRequestString = @"username=sampleuser&pass=samplepass"; NSData *myRequestData = [NSData dataWithBytes: [ myRequestString UTF8String ] length: [ myRequestString length ] ]; NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:[NSURL URLWithString:@"http://somedomain.net/login.php" ]]; [ request setHTTPMethod: @"POST" ]; [ request setHTTPBody: myRequestData ]; NSURLConnection *connection = [[NSURLConnection alloc] initWithRequest:request delegate:self]; [connection release]; [request release]; But how to combine it all together? Just POSTing and calling openURL does not work. Is it possible at all? openURL opens safari and GETs? What if a site could log me in on GET request with username and pass as params, would openURL work then?