# Supper Hard Riddle

Discussion in 'Games' started by Nighteater537, May 15, 2006.

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1. ### Nighteater537 macrumors member

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May 1, 2006
#1
This is something someone showed me 3 years ago, i solved it a year ago, and decided if anyone here can solve it. IT IS HARD. it took me two years.

(i will submit a better pic soon)

Ok here is the rules you must draw the shape above, while following the conditions listed below
You may use only one writing insturement
You may not alter anyline you have drawn
You may not draw over lines
You may not lift up your writing instruement
You may not alter your drawing space (ie, folding or cutting paper)

Also inorder to prove you completed the task, u must submit a "comic strip" of each step

2. ### Jaffa Cake macrumors Core

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#2
I've been trying to beat this one for the past 16 years. I suspect that I may have been told the rules wrong...

3. ### Abulia macrumors 68000

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#3
"Supper hard?" What, we can only do this just before dinner?

4. ### Nighteater537 thread starter macrumors member

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May 1, 2006
#4
Lol, i have the answer, and i bet u can't, i have not descided whether or not i willpost the answer

5. ### jared_kipe macrumors 68030

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#5
Umm according to Euler (the guy who game up with e^ir=cos(r)-isin(r) ) any graph with more than two odd path nodes cannot be completed in an Euler walk, which is what I believe you are describing. Since your graph has 4 odd nodes, it is not possible.

EDIT: It is super hard, as in impossible without changing the rules.

6. ### Jaffa Cake macrumors Core

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#6
16, I repeat, 16 bloody years. You have to...

I should point out (before anyone starts worrying about my sanity) I've not been trying for 16 years solid. I was shown the puzzle in my early teens and couldn't crack it then – but I remember it every six months or so, and have another stab. Mind, the version of the puzzle I was shown had curved bits instead of the pointy bits – I can't help but think the answer lies in those...

7. ### Gasu E. macrumors 601

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Not far from Boston, MA.
#7
It means only people with food-related nicknames are allowed to try this.

8. ### Nighteater537 thread starter macrumors member

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May 1, 2006
#8
there is a logical answer, however, i will give u a hint, the number of lines u see is not the number of lines. how man lines are there?

9. ### Abulia macrumors 68000

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#9
Then I await for you to bless us with your genius (and hopefully some proper English, too).

10. ### Compatiblepoker macrumors regular

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Jacksonville Beach
#10
So is it possible or not? I dont want to spend 16 years on something if its not.

11. ### jared_kipe macrumors 68030

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#11
It is not possible. Is simple to imagine, if you imagine a node with an odd number of lines coming out of it, then you have to return more than you can leave. Which means only diagrams like this with EXACTLY 2 odd nodes will one, such that you start on one, and end on the other.

12. ### Nighteater537 thread starter macrumors member

Joined:
May 1, 2006
#12
it is possible, and dont make fun of my grammer, imgot a 5.5 on my FCAT, its just i dorrnt profread when i type,,,now if anyone plays diablo II i may trade the answer for items in the gaame, or i my give hints, also my clue is very in sightfull.

but there is an even number, learn to count,

i will be in the Aim Chat room: TheRiddle

13. ### clayj macrumors 604

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visiting from downstream
#13
Erm, the point is that if there are MORE than two odd nodes, it's impossible to walk it as you've asked. Your drawing has FOUR nodes with 5 lines exiting each of them.

Obviously.

14. ### Nighteater537 thread starter macrumors member

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May 1, 2006
#14
Hmm, one of us can't count....and i don't think it is me.....

15. ### Gasu E. macrumors 601

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Location:
Not far from Boston, MA.
#15
It doesn't seem possible without a cheat. There are four nodes that have 5 connected lines (and one node with 4 lines). For each node, every time you take a path "into" the node, there must be a path "out" of the node. The only exceptions are the starting and ending node, which can each have an extra path. Therefore there can only be two nodes with an odd number of lines connected.

If that's the case, don't bother trying to solve the puzzle using the obvious rules-- look for a loophole.

****
Apparently other people caught onto this before I posted.

16. ### Nighteater537 thread starter macrumors member

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May 1, 2006
#16
True, it is a loophole....lol that is VERY good wording

17. ### Gasu E. macrumors 601

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Location:
Not far from Boston, MA.
#17
12

18. ### Nighteater537 thread starter macrumors member

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May 1, 2006
#18
wrong!
I feel lonely in this Aim Chat: TheRiddle
wont anyone come>

19. ### Gasu E. macrumors 601

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Location:
Not far from Boston, MA.
#19
Why not; you can't type! Lol

20. ### jared_kipe macrumors 68030

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#20
Yes it is, it is my explanation but glossed up for SOMEONE who is very rude and doesn't act like he is older than 6.

21. ### Nighteater537 thread starter macrumors member

Joined:
May 1, 2006
#21
i feel compelled to tell u that the middle lines can't cross over each other as that will be violating the commandmentss.......
So let me tell u that the shape musty be ddrawn with out going over anylines
That will point u in thhe right direction

22. ### Jaffa Cake macrumors Core

Joined:
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Location:
The City of Culture, Englandshire
#22
I'm thinking 16.

But then I'm the last person you need to be listening to on this one.

23. ### Nighteater537 thread starter macrumors member

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May 1, 2006
#23
i like that, umm no, i am just to lazy to correct my self. I have to leave my computer, However i will be back at 9pm to check the thread, my final hint is
><

24. ### Nighteater537 thread starter macrumors member

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May 1, 2006
#24
Congrads u have ascceneded to the second relization, however your number is still WRONG!

25. ### Gasu E. macrumors 601

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Location:
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#25
Because your problem is boring.

If it's not 12 lines you are playing with words. And then, who cares?

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