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View Full Version : How to POST url in safari?




HARDWARRIOR
Mar 2, 2009, 04:36 AM
Hi!
I want my app to open url in Safari and to login.
I know how to just open URL:

UIApplication *app = [UIApplication sharedApplication];
[app openURL:[[NSURL alloc] initWithString:@"http://www.somedomain.net"]];

But there is a login form on that site. Here is it's code:

<form action="http://www.somedomain.net/login.php" method="post">
...
<td width="68%"><input name="username" class="formlogin" size="23" type="text" /></td>
<td width="10%">&nbsp;</td>
</tr>
<tr>
<td>Password:</td>
<td><input name="pass" class="formlogin" size="23" type="password" /></td>

it looks like I have to POST params to http://www.somedomain.net/login.php
Well, I know how to POST

NSString *myRequestString = @"username=sampleuser&pass=samplepass";
NSData *myRequestData = [NSData dataWithBytes: [ myRequestString UTF8String ] length: [ myRequestString length ] ];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:[NSURL URLWithString:@"http://somedomain.net/login.php" ]];
[ request setHTTPMethod: @"POST" ];
[ request setHTTPBody: myRequestData ];
NSURLConnection *connection = [[NSURLConnection alloc] initWithRequest:request delegate:self];
[connection release];
[request release];

But how to combine it all together? Just POSTing and calling openURL does not work. Is it possible at all? openURL opens safari and GETs? What if a site could log me in on GET request with username and pass as params, would openURL work then?



jjgraz
Mar 7, 2009, 08:39 PM
Not sure if I'm on target with this answer. But I thought it was worth mentioning that many applications log into websites through means of a web Service. For instance. You write the code as you have done, and send it to a PHP file or SOAP file which then logs the user in, and can transfer data to databases ect. Just a thought.