Hi!
I want my app to open url in Safari and to login.
I know how to just open URL:
But there is a login form on that site. Here is it's code:
it looks like I have to POST params to http://www.somedomain.net/login.php
Well, I know how to POST
But how to combine it all together? Just POSTing and calling openURL does not work. Is it possible at all? openURL opens safari and GETs? What if a site could log me in on GET request with username and pass as params, would openURL work then?
I want my app to open url in Safari and to login.
I know how to just open URL:
Code:
UIApplication *app = [UIApplication sharedApplication];
[app openURL:[[NSURL alloc] initWithString:@"http://www.somedomain.net"]];
Code:
<form action="http://www.somedomain.net/login.php" method="post">
...
<td width="68%"><input name="username" class="formlogin" size="23" type="text" /></td>
<td width="10%"> </td>
</tr>
<tr>
<td>Password:</td>
<td><input name="pass" class="formlogin" size="23" type="password" /></td>Well, I know how to POST
Code:
NSString *myRequestString = @"username=sampleuser&pass=samplepass";
NSData *myRequestData = [NSData dataWithBytes: [ myRequestString UTF8String ] length: [ myRequestString length ] ];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:[NSURL URLWithString:@"http://somedomain.net/login.php" ]];
[ request setHTTPMethod: @"POST" ];
[ request setHTTPBody: myRequestData ];
NSURLConnection *connection = [[NSURLConnection alloc] initWithRequest:request delegate:self];
[connection release];
[request release];