macOS Create a Calender matrix

[dukebound85]

Hi all, I have a quick question. I have gridded data I am trying to manipulate and for the sake of existing code I have written (that had this type of index with the data embedded in the netcdf file) would like to create an auxillary matrix with the corresponding time

For instance, I have 12,xxx indexes that correspond to each day between Jan 1, 1979 to Dec 31, 2011

I would like to create a 4x12,xxx array that is of the following behavior

(Record, Month, Day, Year) where each one is 12,xxx in length

Record is the raw index value (1-12,xxx)
Month is the coressponding month of the index value (ie 31 consecutive 1's for Janurary, 28 consecutive 2s for Feb, etc and repeats)
Day is the corresponding day (1-28(31)) for the index
Year is the corresponding year (365 consecutive 1979, then 365 1980s, etc)

Is there an easy way to make this type of array? I would need to take into accoun the leap years and what not

Thanks for any tips

 

[Ron C]

Hi all, I have a quick question. I have gridded data I am trying to manipulate and for the sake of existing code I have written (that had this type of index with the data embedded in the netcdf file) would like to create an auxillary matrix with the corresponding time

For instance, I have 12,xxx indexes that correspond to each day between Jan 1, 1979 to Dec 31, 2011

I would like to create a 4x12,xxx array that is of the following behavior

(Record, Month, Day, Year) where each one is 12,xxx in length

Record is the raw index value (1-12,xxx)
Month is the coressponding month of the index value (ie 31 consecutive 1's for Janurary, 28 consecutive 2s for Feb, etc and repeats)
Day is the corresponding day (1-28(31)) for the index
Year is the corresponding year (365 consecutive 1979, then 365 1980s, etc)

Is there an easy way to make this type of array? I would need to take into accoun the leap years and what not

Thanks for any tips

I wouldn't store that information, rather I'd compute it for a given index.

I'd start by figuring out how to convert the index into the appropriate NSTimeInterval value, then I'd use the NSDate and NSDateComponents classes to help me figure out the information I'm looking for. Read the documentation for more information on these classes, particularly the "Date and Time Programming Guide" - it gives you the answer in a section titled "Converting between Dates and Date Components."

 

[chown33]

1. Which language?

2. The intended meaning of "12,xxx" is unclear (though it might be clearer if we knew which language). Do you mean "approximately 12 thousand (~12,000, ~12k, ~12e3)" since the number of days in your date range is approximately 12 thousand (12,053)? Or do you mean "twelve" and the ",xxx" has some additional meaning? Or do you mean something else?

 

[subsonix]

What language are you using? There are date functions available to do what you want without storing every date in an array.

 

[dukebound85]

I am creating the array in matlab. The 12,xxx is more explicitly 12,053 values

here is how I initially approached the problem.

%% Calender maker

record = [1:1:12053];

y79 = [1:1:365];
y80 = [1:1:366];
y81 = [1:1:365];
y82 = [1:1:365];
y83 = [1:1:365];
y84 = [1:1:366];
y85 = [1:1:365];
y86 = [1:1:365];
y87 = [1:1:365];
y88 = [1:1:366];
y89 = [1:1:365];
y90 = [1:1:365];
y91 = [1:1:365];
y92 = [1:1:366];
y93 = [1:1:365];
y94 = [1:1:365];
y95 = [1:1:365];
y96 = [1:1:366];
y97 = [1:1:365];
y98 = [1:1:365];
y99 = [1:1:365];
y00 = [1:1:366];
y01 = [1:1:365];
y02 = [1:1:365];
y03 = [1:1:365];
y04 = [1:1:366];
y05 = [1:1:365];
y06 = [1:1:365];
y07 = [1:1:365];
y08 = [1:1:366];
y09 = [1:1:365];
y10 = [1:1:365];
y11 = [1:1:365];

day = [y79,y80,y81,y82,y83,y84,y85,y86,y87,y88,y89,y90,y91,y92...
    y93,y94,y95,y96,y97,y98,y99,y00,y01,y02,y03,y04,y05,y06,...
    y07,y08,y09,y10,y11]';

I have netcdf files with length of the record dimension and am trying to manipulate it via data so hence my complimentary matrix I am attempting to recreate if that makes sense

Edit: Figured it out...even though my code to generate it is not the most elagant!