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Anyone want to help me with my Calculus homework? it would be greatly appreciated :)

C

christall109

macrumors 6502
Original poster
Jun 15, 2007
351
5
Hey Guys so here's the problem:

Solve for n.

x^4 = x^(2n) times (-2x)^(n-11)

Any advice would be greatly appreciated. I know there has to be math geniuses out there!
 
well I tried with the logs but got a invalid domain..

so what i did was just set 4=2n + n - 11 and got n=5

Is that correct?
Thanks for the help!
 
Anyone want to help me with my Calculus homework? it would be greatly appreciated :)

Only if you wish to fail.

This puts me in mind of a scene from the movie The Day The Earth Stood Still.

Barnhardt: Have you tested this theory?
Klaatu: I find it works well enough to get me from one planet to another.
Click to expand...
 
KompleX said:
did you mean this????
x^(4) = x^[(2n)*(-2x)^(n-11)]
Click to expand...

i kind of read it as x^4 = [x^(2n)]*[(-2x)^(n-11)].

the lazy person in me wants to move all the x's on one side and everything else to the other. and i do know that n = 6.5 is a solution for x = -2. i don't have any paper, so i can't think to make n as a function of x.

christall109 said:
so what i did was just set 4=2n + n - 11 and got n=5

Is that correct?
Thanks for the help!
Click to expand...

because of the -2, you can't do this.
 
Transform the equation into

x^4 = (x^2)^n * (-2x)^n * (-2x)^(-11)

Then collect the ^n terms on one side, so that you only have one ^n term, and the rest on the other side. Then you can log it up.
 
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