So, I could really use some help in here. It's for my lab report, and I am utterly clueless.
We had 3 reactions:
NaOH + HCl -> H2O
NaOH + NH4Cl -> NH3 + H2O
HCl + NH3 -> NH4Cl
We calculated maximum and minimum temperatures for each of the reactions in a calirometer.
Reaction 1) Max = 34.24, Initial = 22.41
Reaction 2) Max = 22.17 ,Initial = 21.89
Reaction 3) Max= 34.32, Initial = 22.57
Questions:
Question 1:Calculate the amount of heat energy, q, produced in each reaction. Use 1.03g/mL for each density, use 4.18 J/(g*C) for specific heat of all solutions.
Reaction 1) 1.03g/mL * 50mL = 51.5 g (11.83)(4.18) = 2550 J
Reaction 2) 51.5g (-0.28)(4.18) = -60 J
Reaction 3) 51.5g(11.75)(4.18) = 2530 J
*Correct? Thoughts?*
Question 2: Calculate the enthalpy change, ∆H, for each reaction in temrs of kJ/mol of each reactant
Reaction 1) 2.55 kJ/.10 mol = 25.5 kJ/mol
Reaction 2)-.060 kJ/.10 mol = .6 kJ/ mol
Reaction 3) 2.53 kJ/.10 mol = 25.3 kJ/mol
*Is that right?*
Question 3: Use your answers from 2 above and Hess's law to determine the experimental molar enthalpy for Reaction 3.
*No clue*
Question 4: Use Hess's Law, and the accepted values of ∆H in the Pre-Lab exercise to calculate the ∆H for Reaction 3. How does the accepted value compare to your experimental value?
* NO clue*
We had 3 reactions:
NaOH + HCl -> H2O
NaOH + NH4Cl -> NH3 + H2O
HCl + NH3 -> NH4Cl
We calculated maximum and minimum temperatures for each of the reactions in a calirometer.
Reaction 1) Max = 34.24, Initial = 22.41
Reaction 2) Max = 22.17 ,Initial = 21.89
Reaction 3) Max= 34.32, Initial = 22.57
Questions:
Question 1:Calculate the amount of heat energy, q, produced in each reaction. Use 1.03g/mL for each density, use 4.18 J/(g*C) for specific heat of all solutions.
Reaction 1) 1.03g/mL * 50mL = 51.5 g (11.83)(4.18) = 2550 J
Reaction 2) 51.5g (-0.28)(4.18) = -60 J
Reaction 3) 51.5g(11.75)(4.18) = 2530 J
*Correct? Thoughts?*
Question 2: Calculate the enthalpy change, ∆H, for each reaction in temrs of kJ/mol of each reactant
Reaction 1) 2.55 kJ/.10 mol = 25.5 kJ/mol
Reaction 2)-.060 kJ/.10 mol = .6 kJ/ mol
Reaction 3) 2.53 kJ/.10 mol = 25.3 kJ/mol
*Is that right?*
Question 3: Use your answers from 2 above and Hess's law to determine the experimental molar enthalpy for Reaction 3.
*No clue*
Question 4: Use Hess's Law, and the accepted values of ∆H in the Pre-Lab exercise to calculate the ∆H for Reaction 3. How does the accepted value compare to your experimental value?
* NO clue*