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SChaput

macrumors regular
Original poster
Jul 2, 2008
153
0
United States
Hello,

I'm trying manipulate the website, http://www.video2mp3.net by an external site.

I'm trying to mimic the ajax calls they make so that i can reproduce the output. Everyone i ask about this tells me to view the information in firebug. However, when I view firebug, frankly, I'm not sure what I'm looking at.

Is it true that firebug will be able to give me all the information I need?

Thanks!
 
It won't tell you everything, only what gets sent to the server and what is returned, but not what happens on the server. You may need to use FirePHP as well with Firebug. There are some Firebug tutorials online you can check out to get more comfortable with it.
 
I've installed FirePHP, pretty cool little tool. However, I'm still unable to mimic the functionally of the site. I currently have it set up at http://www.stevechaput.com/testing and I have my own check.php ../testing/check.php.

But when I run my own page through firePHP it doesn't seem to be sending anything at all.

Am I not setting up the ajax properly? Thanks!
 
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