Help with exact solutions of cubic root

[4409723]

Hello,

I've been working through a problem an arrived at x^3-3x+1. I can solve this using the simultaneous equation solver of my calculator but this gives me decimal answers. Is there a way to get this exactly? Anybody with mathematica handy care to lend me a hand?

Thanks for any help,

Wes

 

[Kobushi]

Heh... here's what MatLab spits out.... for what it's worth.


Stupid cubics and their complex roots. (those are 3 different roots, and I already ran <simplify> )


1/2*((-4+4*i*3^(1/2))^(2/3)+4)/(-4+4*i*3^(1/2))^(1/3)

1/4*(-(-4+4*i*3^(1/2))^(2/3)-4+i*3^(1/2)*(-4+4*i*3^(1/2))^(2/3)-4*i*3^(1/2))/(-4+4*i*3^(1/2))^(1/3)

-1/4*((-4+4*i*3^(1/2))^(2/3)+4+i*3^(1/2)*(-4+4*i*3^(1/2))^(2/3)-4*i*3^(1/2))/(-4+4*i*3^(1/2))^(1/3)