How to come back to application from safari.
Problem:-
On button click ->
"[[uiapplication sharedapplication] openurl:[nsurl urlwithstring
"https://forums.macrumors.com"]];"
Now how can i back on application from this safari browser...
Help me out its urgent !!
Thanks in advance
Problem:-
On button click ->
"[[uiapplication sharedapplication] openurl:[nsurl urlwithstring
Now how can i back on application from this safari browser...
Help me out its urgent !!
Thanks in advance
Last edited by a moderator: