Need A Calculator - Convert FPS to Minutes and Seconds

[John Doe 57]

I filmed a track meet the other day and the some of the results will not be posted online. So I have footage of races with no time result. I filmed from when the the gun went of to when the runner crossed the finish line. I just need to subtract the frames from when they finish, from when the gun goes off. I have tried some online calculators, but they round the answer back to 29.97 fps. So no answer will read xx.29 or higher. I am using iMovie HD, with 29.97 fps. I'm not sure if I'm using drop frames or non-drop frames. Thanks.

 

[LethalWolfe]

Video is 29.97 frames per second so you can't get anymore accurate than 1/30th of a second.


Lethal

 

[John Doe 57]

Video is 29.97 frames per second so you can't get anymore accurate than 1/30th of a second.


Lethal

Alright. Where could I get a calculator though?

 

[LethalWolfe]

Here's one that's a widget. Link

Lethal

 

[John Doe 57]

Here's one that's a widget. Link

Lethal

Thanks, but I'm still confused. Here is an example of my problem:

The gun goes off at 5:49:19 (Minutes Seconds Frames), the runner crosses the finish line at 6:00:16. I need to know in seconds, how long it took him to finish. Sorry, I'm just not very good at this or at math in general.

 

[EX1127]

Thanks, but I'm still confused. Here is an example of my problem:

The gun goes off at 5:49:19 (Minutes Seconds Frames), the runner crosses the finish line at 6:00:16. I need to know in seconds, how long it took him to finish. Sorry, I'm just not very good at this or at math in general.

Can you not subtract end from beginning? or am i not understanding the question?

 

[CaptainChunk]

With that calculator widget that Lethal posted, you can subtract the beginning timecode from the end timecode and get a result in timecode format.

And from there, it's simple math converting the frames to a decimal value. You would divide the number of frames at the end by 29.97. Example:

The difference between the times you posted at 29.97 drop-frame (typical for DV) would be 10:27 (seconds:frames). 27 divided by 29.97 is about 0.901 seconds. Therefore, the runner's time in the case would be 10.901 seconds.

There will be a margin of error as stated earlier in this thread because the video isn't any more accurate than about a 1/30th of a second to begin with.

 

[John Doe 57]

With that calculator widget that Lethal posted, you can subtract the beginning timecode from the end timecode and get a result in timecode format.

And from there, it's simple math converting the frames to a decimal value. You would divide the number of frames at the end by 29.97. Example:

The difference between the times you posted at 29.97 drop-frame (typical for DV) would be 10:27 (seconds:frames). 27 divided by 29.97 is about 0.901 seconds. Therefore, the runner's time in the case would be 10.901 seconds.

There will be a margin of error as stated earlier in this thread because the video isn't any more accurate than about a 1/30th of a second to begin with.

Thank you!!! That is what I needed. 1/30th will have to do, I just needed something pretty close.