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twistedlegato

macrumors 65816
Original poster
Jun 15, 2006
1,494
1
I know this is probabley very easy for most of you, but let i remind you, i am in pre-algabra, though i am in a gifted class!

Given the equations, determine the slope of the line.
Give the y-intercept.

1) 5x+2y=7


2)7x+3y=9


Thanks alot!:)
 
1) 5x+2y=7
2)7x+3y=9

1. Gradient -2.5, y intercept 3.5
2.Gradient -2 and 1/3, y intercept 3
Is this correct or am i being really stupid??

Rats just beaten. Make the integer infront of y=1.
y= mx + c where m is the gradient and c is the y intercept. Make x=0 and the y intercept is obvious and the gradient is the integer infront of the x. Is this explained well enough??
 
Can you explain?

There are two ways to find gradient and point of intercept. The easiest for this solution is:

y=mx + c

(m being the gradient, and c the y intercept)

rearrange the equations to y=....
find the number of x's (this is the gradient, and the other number, the y intercept)

1. y= -2.5x + 3.5
2. y= -7/3x + 3
 
5x + 2y = 7
=>2y = 7-5x
=>y = 3.5-2.5x

3.5 is intercept, -2.5 is slope

7x + 3y = 9
=>3y = 9 - 7x
=> y = 3 - 7/3x

3 is intercept, -7/3 is slope


AHHHH!

I learned to do it with fraction, not decimals so i was cunfused!

Thanks everyone!
 
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