Hi folks. This case may have been mentioned/discussed previously in other threads related to the new slim and feather light 12" rMB. My apologies, if this is repetition!...
I recently came over a review posted sometime in May this year. The reviewer was claiming that he managed o charge the 12" rMB (while in "off" or "sleep" mode, only) with the 2.1A (or maybe 2.4A) output of the the standard 5.0Vdc output of an external (portable) hi-capacity power bank. He concluded, it took much longer to complete a charge cycle: like 5-6 hrs.
I addressed him privately and he re-confirmed the case and added he also tried with several other power banks. But he failed to give the technical explanation as how it was possible to charge his laptop (which normally is charged with 14.0Vdc @ 2.0A) only with a regulated (fixed/stable) 5.0Vdc source (the power bank's output).
An explanation came from another guy, indicating that there "should be" a SEPIC topology converter in the laptop which actually converts the 5.0Vdc input to a higher voltage (possibly 15.0Vdc).
This explanation sounds "reasonable"; yes there are such ICs custom built for the said voltage multiplication, battery monitoring, etc. But I'm not 100% sure if there's one of these ICs inside the mentioned Apple laptop...???
But still I cannot fully dig out why Apple (if, yes) has opted this circuitry: what's the big idea behind charging the laptop while it's only inoperative and at a very slow rate than the normal?
Any ideas or comments, mostly welcomed...
I recently came over a review posted sometime in May this year. The reviewer was claiming that he managed o charge the 12" rMB (while in "off" or "sleep" mode, only) with the 2.1A (or maybe 2.4A) output of the the standard 5.0Vdc output of an external (portable) hi-capacity power bank. He concluded, it took much longer to complete a charge cycle: like 5-6 hrs.
I addressed him privately and he re-confirmed the case and added he also tried with several other power banks. But he failed to give the technical explanation as how it was possible to charge his laptop (which normally is charged with 14.0Vdc @ 2.0A) only with a regulated (fixed/stable) 5.0Vdc source (the power bank's output).
An explanation came from another guy, indicating that there "should be" a SEPIC topology converter in the laptop which actually converts the 5.0Vdc input to a higher voltage (possibly 15.0Vdc).
This explanation sounds "reasonable"; yes there are such ICs custom built for the said voltage multiplication, battery monitoring, etc. But I'm not 100% sure if there's one of these ICs inside the mentioned Apple laptop...???
But still I cannot fully dig out why Apple (if, yes) has opted this circuitry: what's the big idea behind charging the laptop while it's only inoperative and at a very slow rate than the normal?
Any ideas or comments, mostly welcomed...