Please help me REALLY REALLY quick.

[gregdrummeraz]

Each square root is between two integers. Name the two integers.

Which do you think?

5 and 6
6 and 7
4 and 5
7 and 8


I am seriously confused..


"brain fart"!!!

 

[gregdrummeraz]

I POSTED IT WRONG.. HERES THE PROBLEM.


Each square root is between two integers. Name the two integers.

√27

5 and 6
6 and 7
4 and 5
7 and 8

 

[richard.mac]

yeh i thought the first question was posted wrong, it made no sense.

well sqrt(27) = 5.20 (3sf) so thats between 5 and 6… easy!

 

[swiftaw]

I POSTED IT WRONG.. HERES THE PROBLEM.


Each square root is between two integers. Name the two integers.

√27

5 and 6
6 and 7
4 and 5
7 and 8

If you don't have a calculator, realize that 25 < 27 < 36, so sqrt(25) < sqrt(27) < sqrt(36)

Therefore

5 < sqrt(27) < 6

 

[prostuff1]

um, yeah, this is easy

5^2 = 25 and 6^2 = 36

since 27 is between 25 and 36 then the sqrt(27) must be between 5 and 6.

 

[gregdrummeraz]

So the two sqr of 81 are 9, -9?

 

[prostuff1]

So the two sqr of 81 are 9, -9?

depend on were the negative in -9 is.

example:

9^2 = 81
(-9)^2 = 81
-(9)^2 = -81

understand?

Edit: for your question though the answer is yes. 9 and -9 are the squares of 81

 

[richard.mac]

^ and the sqrt(-81) = 9i

though that doesnt really apply here

 

[gregdrummeraz]

What do I press on a calculator to find simplest form of a fraction?

I am def on my macbook... using leopard. so what would it be?