Anyone know how to use Graphmatica?

Discussion in 'Community Discussion' started by Eric Lewis, Nov 11, 2007.

  1. Eric Lewis macrumors 68020

    Eric Lewis

    Joined:
    Feb 4, 2007
    Location:
    CANADA? eh?
    #1
    I am trying to make a circle which is i believe

    ( x ) ^2 + ( y )^2 = 8

    I need to make it smaller and move it up 6 and over to the left 2?

    How do i do this?

    Can you please help!

    Thanks
     
  2. Jasonbot macrumors 68020

    Jasonbot

    Joined:
    Aug 15, 2006
    Location:
    The Rainbow Nation RSA
    #2
    To move it horizontally you need to change the p value

    To move it vertically you need to change the q value

    To make it smaller you need to change the r value

    The equation of a circle is:
    r^2=(x+p)^2+(y+q)^2

    to change p if you subtract from p teh graph moves forward and if you add it moves backwards.
    so in the graph we need to change p by a factor of 2 to the left. left is negative so we need to add 2. so (x+2)^2

    to change q its the same story. we need to move it up 6 so we subtract 6. so (y-6)^2

    so our new equation is 8=(x+2)^2+(y-6)^2

    finally to change the graphs size we need to merely change the radius by just changing 8 to anything smaller than 8.

    On a side note, I prefer grapher for making graphs in OS X :D
     
  3. siurpeeman macrumors 603

    siurpeeman

    Joined:
    Dec 2, 2006
    Location:
    the OC
    #3
    it would be easier to go with the same equation with minuses instead of pluses.

    r^2=(x-p)^2+(y-q)^2

    that way, a positive p-value would represent a positive x movement, and the same with q.
     
  4. Jasonbot macrumors 68020

    Jasonbot

    Joined:
    Aug 15, 2006
    Location:
    The Rainbow Nation RSA
    #4
    my bad...
     
  5. jerard018 macrumors newbie

    Joined:
    Aug 17, 2008
    #5
    does anybody know how to use graphmatica??

    does anybody know how to use graphmatica??.. thanks....
     

Share This Page