No, you are wrong. In the Q&A it was stated that Apple store return rates were lower than AT&T return rates. To his credit, he actually stated the "worst case scenario" in his presentation.
You're right. I missed that.
No, you are wrong. In the Q&A it was stated that Apple store return rates were lower than AT&T return rates. To his credit, he actually stated the "worst case scenario" in his presentation.
Nope, sorry. Have a closer look at your formula. Here's a simplified version of what you wrote:
a/c * c/d * d/b = a/b
That's the same as writing:
a/b * c/c * d/d = a/b
Now c/c = 1, and d/d = 1, so your formula just becomes:
a/b = a/b
Apple said that 80% of the 3GThey don't really make reporters like they used to. Apple gave journalism a chance but most of them were too easy. Perhaps of fear of not getting re-invited in the future, who knows.
Anyway, and this may have already been asked... The one question however, I would've liked to hear Apple's honest answer too is this:
How (and why) was the tiniest but worst spot to touch the phone placed where it is most likely to be touched?
Does anyone know?
Wrong. When you grip the phone, you are ALREADY bridging the antennas. So that issue is not isolated from the gripping issue.
Your simplification is valid only in terms of units, not for the values. For example, the c in the denominator of a/c is not the same value as the c in the numerator of c/d, so you can't use the same variable in both places. Let me demonstrate with a conversion of the speed of sound from meters per second to mph:
343 m/s * 3600 s/h * 0.00062137 miles/m = 767 mph.
In the first term, the value of seconds is 1 (the denominator); in the second term, the value of seconds is 3600 (the numerator). You aren't able to use the same variable to express both of these values in the equation.
Don't be too proud of this technological terror Apple has constructed. The ability to take HD video on a Retina Display is insignificant next to the power of a strong phone signal.
Apple said that 80% of the 3Gowners purchased a case for their iPhone, in the Apple Stores (now only 20%) so why would this be any different for the iPhone 4? It is after all still a pretty expensive phone.
Not to mention that Apple reduced the size of the phone, so that adding a case would be less of an issue, and they even made their own bumper for it. Instantly resolving the antenna attenuation [in weaker reception areas].
Look at it this way: Apple was in need of extra battery capacity – to support the A4 and IPS/retina display – and thus they did something completely new. Something that wasn't done before.
Also. The antenna has to be at the bottom, and the wave length forced them to have it in this spot.
You may not like it, but that's basically it.
Tip: I applied a thin layer of transparent coating, at the specific corner, and that solved it for when I am working from my sailboat, where reception is almost always bad. I hope this helps anyone
Apple's attempt to draw RIM into Apple's self-made debacle is unacceptable. Apple's claims about RIM products appear to be deliberate attempts to distort the public's understanding of an antenna design issue and to deflect attention from Apple's difficult situation. RIM is a global leader in antenna design and has been successfully designing industry-leading wireless data products with efficient and effective radio performance for over 20 years. During that time, RIM has avoided designs like the one Apple used in the iPhone 4 and instead has used innovative designs which reduce the risk for dropped calls, especially in areas of lower coverage. One thing is for certain, RIM's customers don't need to use a case for their BlackBerry smartphone to maintain proper connectivity. Apple clearly made certain design decisions and it should take responsibility for these decisions rather than trying to draw RIM and others into a situation that relates specifically to Apple.
The 'value of seconds' in both cases can be exactly the same. It's irrelevant. 's/h' is a constant. The ratio of seconds to hours never changes. If you increase the number of seconds, you increase the number of hours, but the ratio 's/h' remains constant at 3600.
So okay, it might make sense to structure your equation like that if you had each of those three ratios at hand. It would be even simpler if you just knew the ratio of "iPhones with issues"/"# calls"
Actually that figure is essential.
Apple cited the 0.55% figure in an effort to demonstrate that reception issues with the iPhone 4 are not widespread. How can you define "widespread" - as the percentage of iPhone 4s with reception issues:
We want to know the ratio of: "iPhone with issue" / "total iPhones".
Apple calculated the ratio of: "calls about reception" / "total iPhones".
As you notice, the two units are not the same. What does that mean? It means that you can not use Apple's figure of 0.55% to infer how many iPhone 4s are affected - which is exactly what they did. To estimate the ratio we want to find, you need this formula:
X ("iPhone with issue"/"users who report issue") * Y ("users who report issue"/"# calls") * Z ("# calls"/"total iPhones") = G ("iPhone with issue"/"total iPhones")
Z is the figure Apple provided us with.
Y is the ratio of how many people visit the genius bar compared to calling Apple Care
X is what you call "irrelevant" above.
All three figures are essential to calculate an actual estimate as to the number of iPhone 4 users with reception issues.
Since apple instead quoted 0.55% with the intention of portraying the percentage of iPhone 4 users with reception issues, their figures are misleading.
But with any other smart phone you're not bridging the antennas, you're muffling the signal.
Steve tried to compares to oranges to trick us.
The response from RIM
Lawsuits againstin the near future perhaps.
I was assuming that apple provided iPhone 4's official cases for this specific technical issue as they knew about it before releasing date, but it seems that they already have the concept about death grip issues for smart phones.
You said that if you rearrange my equation, you get two terms where c/c = 1 and d/d = 1, so it's meaningless.
However, if you rearrange the terms in the speed of sound conversion to collect s/s, it's not equal to 1. It's equal to 3600/1. Understand?
You seem to think that I just picked three ratios out of the blue. Rather, I started with the statistic Apple provided, which was "# calls"/"total iPhones". In order to find the meaningful ratio of "iPhones with issue"/"total iPhones", you need to do a unit conversion.
I bet we're going to eventually see a throw down using db or some other metric instead of bars.
a/b * c/c * d/d = a/b
Now c/c = 1, and d/d = 1, so your formula just becomes:
a/b = a/b
343 * 3600 * 0.00062137 = 767/1
1234800/3600 * 3600/1 * 767/1234800 = 767/1
767/1 * 1234800/1234800 * 3600/3600 = 767/1
767/1 = 767/1
No, no, no. Your choice of 3600 in one instance and 1 in another is arbitrary and inconsistent.
This is exactly the same, but with actual values this time. Understand?