Grapher and odd roots

Discussion in 'Mac Apps and Mac App Store' started by freedrinks, Oct 15, 2007.

  1. freedrinks macrumors newbie

    Jun 5, 2007
    Any one notice that grapher will not graph the negative inputs for any function f(x)=x^a/b if b is odd and a>1. Any one know why this is?
  2. MisterMe macrumors G4


    Jul 17, 2002
    You did not accurately describe the "problem." However, the answer is simple. Grapher is a simple program. It does not intelligently handle imaginary or complex values of functions like yours.
  3. raindancer macrumors newbie

    Feb 4, 2008
    I'm coming onto this late, but it's a perfectly reasonable question. y=x^(2/3) does not involve any imaginary or complex numbers, and is equal to y=(x^(1/3))^2, which it will graph.

    I think it's an interesting blip of stupidity in an otherwise semi-smart app.

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