Grapher and odd roots

Discussion in 'Mac Apps and Mac App Store' started by freedrinks, Oct 15, 2007.

  1. freedrinks macrumors newbie

    Joined:
    Jun 5, 2007
    #1
    Any one notice that grapher will not graph the negative inputs for any function f(x)=x^a/b if b is odd and a>1. Any one know why this is?
     
  2. MisterMe macrumors G4

    MisterMe

    Joined:
    Jul 17, 2002
    Location:
    USA
    #2
    You did not accurately describe the "problem." However, the answer is simple. Grapher is a simple program. It does not intelligently handle imaginary or complex values of functions like yours.
     
  3. raindancer macrumors newbie

    Joined:
    Feb 4, 2008
    #3
    I'm coming onto this late, but it's a perfectly reasonable question. y=x^(2/3) does not involve any imaginary or complex numbers, and is equal to y=(x^(1/3))^2, which it will graph.

    I think it's an interesting blip of stupidity in an otherwise semi-smart app.
     

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