I guessed B, because for single digits, the number increases 2 for every 10 numbers, plus 20 for the 40s and 90s.
I counted in my head without looking at your answers and camera up with the number 167 lol, so i picked B as it nearer and i might have miscounted along the way.
ok it's definitely B/166, as i have figured out how it got 167 by mistake. I forgot that the number '49' doesn't need to be counted twice.
for N in {1..300}
do
echo $N
done \
| grep -v '[49]' \
| head -n 125 | tail175
176
177
178
180
181
182
183
185
186It's a sequence of bash commands that produces the output given. You can paste the first CODE section into a Terminal window and it should produce the output shown in the 2nd CODE section.
I have just realised that when i add the 43 to 125 to get 167, that is wrong because there are some numbers between 125 and 167 that contain 4's and 9's too.
var currentRoom = 1, n = 0;
while (currentRoom <= 125){
n++;
if (n.toString().search(/[49]/) == -1)
currentRoom++;
}
console.log(n);var r_num = 1
var r_cnt = 1
var whichRoom = 125
while ( r_cnt <= whichRoom ) {
if ( r_num.toString().search(/(9|4)/) == -1 ) {
r_cnt++;
}
r_num++;
}
alert( r_num - 1 );You've only posted a hypothetical SQL "ruler". Even a cat can claim to be a king.
I recognized it as an actual query, but your original post didn't include initial conditions, such as creating a table with a suitable name, and an appropriate number of entries.With detail as (
Select rrn(a) roomNumber
From tableName a
Where rrn(a) not like (‘%4%’, ‘%9%’)
Order by rrn(a) asc
Fetch first 125 rows only
)
Select max(a.roomNumber) answer
From detail a;
Answer = 186
I provided the actual query. Pretty elegant huh?
Substitute tableName for any table with >/= 186 rows.
I'll give you an extension to submit completed homework. Howzzat?The query doesn’t need to create a table to execute, it uses a logical table named “detail”. “Detail” contains one column aptly named roomNumber and populated with the relative record numbers based on the where clause (excluding rrn’s containing 4,9). Then it selects the max roomNumber which is 186.
It does, however, require the existence of any physical table (tableName) with >= 186 rows. I thought that assumption was declared.
Please reconsider and give me an A or retest.
Ps - I probably could accomplish it with simply:
Select max(rrn(a)) roomNumber
From tableName a
Where rrn(a) not like (‘%4%’, ‘%9%’)
Order by rrn(a) asc
Fetch first 125 rows only;
But I’ve been too lazy to log in to confirm my result and syntax.
var roomNumber = 1, x = 0
repeat {
x += 1
if String(x).contains("4") || String(x).contains("9") {
continue
}
roomNumber += 1
} while roomNumber <= 125var currentRoomNo = 1, n = 0
while currentRoomNo <= 125 {
n += 1
if String(n).contains("4") || String(n).contains("9") {
continue
}
currentRoomNo += 1
}I manually counted and the answer is definitely 186.
I read about it years ago. I've replied to some threads in the Mac Programming forum that involve Project Euler questions. I just searched there for "Euler" and found a couple dozen posts, but not many with my replies. I did recognize some of the Euler threads, and can see why I didn't reply. I can also see why I did reply in some threads mentioning "Euler".@chown33, very elegant solution.