I don't think you understand how light-guides and diffusers work in an LCD panel. The LEDs don't "project" anywhere, the light is fed into a light-guide, transported to key locations, and a diffuser spreads it out evenly from there.
And in that process, light is lost. Look at that article and the measured output. Notice the uneven distribution of intensity? That's a result of loss due to imperfections in the backlight, namely in the ability of the light guide to deliver light from the edges in a perfect fashion.
If we depended on the "projection" capabilities of the LED, we'd have severely unbalanced backlighting.
We do and we do. Look at the variation. LEDs are driven at 4300 nits, delivering actual brightness of 3076-4132 nits on the display.
My point was relating to light-guides ONLY, which is a completely analogous problem to optical fiber.
With compounding errors abound. An LCD backlight is not like one, point-to-point fiber link with less than 0.1% loss. It's analogous to hundreds to thousands of them, only instead of being wrapped in nice little reflective jackets, they're etched onto an open face sheet of plastic.
The final brightness is then again 0.35W/sq ft!
You're conveniently leaving out the part about what that brightness level is and how consistent it is across the surface of the display, which are the only relevant concerns. Of course doubling power will result in the same wattage per unit of area, but you're not actually demonstrating the luminance of that power output. And you can't, because there's not enough information in your example to make any calculation.
The larger an LCD gets, the more light it blocks because of the greater number of traces physically obscuring the light, even if pixel density remains constant. The light guide is also impacted. The etched surface can only carry so much light so far. Having to transport light longer distances means more channels and reflective structures and more loss along the way. It also means more careful work in the channels closest to the LEDs to prevent excess leakage. All of this contributes to higher power consumption.
It's the same reasons, albeit on a smaller scale, why retina displays need so much more backlight power: it is harder to get the light where it needs to go the more you put between the LED and the measuring instrument.
In just one
example, you can see that the relative power efficiency of the larger iPad displays cannot match that of the smaller iPhone. That's due to a combination of factors and is not chiefly because of the screen size difference, but it is part of the equation. This
PDF contains a number of insights, such as that relative power consumption of TVs continues to grow as their size increases, offset partially but not completely by efficiency improvements in backlights. An edge-lit 46" TV had a typical 324 LEDs, with comparable 32" models at 100 LEDs, both typically 0.32W apiece. So that's roughly double the area (903 sq in vs. 437), but more than triple the power.
No. It's not a "combination" of both. The ONLY losses are at the interface. Hence the name Total Internal Reflection.
If each medium were capable of achieving 100% TIR, that would be true. But they're just not. PMMA is very
good, with losses below 5%, but it's not zero.
Every material absorbs some light. We have no perfect reflectors or transmitters.