Nope. No jailbrooken.
well it may be jailbrooken... just not jailbroken![]()
This thread is just going to confuse people and cause them to think that a jailbreak for 7.1 has been released.![]()
Most likely isn't going to be released as I believe it utilizes the iBoot exploit ih8sn0w found
The iBoot exploit is only exploitable if the device is already jailbroken. In summation, it's nearly useless.
The iBoot exploit is only exploitable if the device is already jailbroken. In summation, it's nearly useless.
There's been some controversy around it with ih8sn0w and musclenerd but not too sure about it yet. ih8sn0w hasn't tested it yet to see if it works on non-jailbroken device yet (not video evidence yet though)
Of course it works. iBoot exploits are loaded before a kernel even begins![]()
well it may be jailbrooken... just not jailbroken![]()
**** *******! I have dyslexia!
**** *******! I have dyslexia!
Be nice if/when a jb for 7.1 comes. Crashes are starting to bug me on 7.04
The untethered component seems to be most often the harder aspect of a jailbreak to discover, so this is needed regarldess of a bootrom exploit being available on the iPhone 4/A4.
That said, this could also bode well for all devices on an iOS 7.1 jailbreak, depending on if the developer releases it despite going to work for Apple ...
The untether always seemed like the easier aspect, when the iPhone 3GS came out there was a jailbreak literally like a day or so later because the 24k pwn bootrom exploit was there. Same when the limera1n bootrom exploit came out for the 4 and lower.
Limera1n is the bootrom exploit, not the untether, which is why the 4 always has a tethered jailbreak (and potentially untethered it appears).