iPhone Extract URL from XML enclosure

I am working on getting the URL from the following inside an XML:

Code:

<item>
		<title>Accomidations on Your Trip</title>
<link>http://treymorgan.podbean.com/2012/06/05/accomidations-on-your-trip/</link>
		<enclosure url="http://treymorgan.podbean.com/mf/feed/bf8mvq/Accommoditions.mp3" length="29865594" type="audio/mpeg"/>
				</item>

I just need the URL of the mp3. I am using GDataXML and I know I need to use GDataXMLNode to get the attributeForName enclosure, but not sure how to do it. Right now I have:

Code:

- (void)parseRss:(GDataXMLElement *)rootElement entries:(NSMutableArray *)entries {
    
    NSArray *channels = [rootElement elementsForName:@"channel"];
    for (GDataXMLElement *channel in channels) {            
        
        NSString *blogTitle = [channel valueForChild:@"title"];                    
        
        NSArray *items = [channel elementsForName:@"item"];
        for (GDataXMLElement *item in items) {
            NSString *articleTitle = [item valueForChild:@"title"];
            NSString *articleUrl = [item valueForChild:@"link"];            
           
            GDataXMLNode *nodes = [item attributeForName:@"enclosure"];
            NSLog(@"%@", nodes);

        }      
    }
    
}

The NSLog comes back as null for each entry...Any thoughts?