I have no idea how poker dice works, but i have extensive knowledge of texas hold'em poker and poker odds and I will mention one point which may or may not be relavent as far as poker dice is concerned. If poker dice involves betting money in between rolls which would be the equivalent of betting rounds pf, flop, turn, and river as in texas hold'em then you shouldn't simply let probabilities dictate next action but the probability of improving to the best hand in relationship to money in the pot and the cost to see the next card, in other words how much you will need to potentially call in relationship to the pot that you can win in relationship to the probability that you can win the hand.
For example, and my apologies in advance if this has no application in the poke dice world, but suppose you're on the flop with a flush draw on a drawy board with a possible straight, for example JKT and you suspect that your opponent could have a made straight but you figure that if you hit your flush then you will win the hand. Suppose the pot has $1,000 and your opponent leads out with a $500 half pot bet. the pot odds are 1,500:500 or 3:1. the probability of hitting your flush with one card to come is about 4:1 (9 outs is about a 19%) or with two cards to come it's 2:1 (9 outs with 2 cards to come is in the range of 36% but for simplicity sake we round down to 33% which translates into 2:1 odds). If you are determined to ride the hand to the river and see both cards then you have the right odds to call the $500 bet because you are getting 3:1 on your money with only 2:1 odds to make your hand, thereby making this a profitable play and plus EV (expected value) in the long run. if you are only going to see one card, then you do not have the right odds to call, because you are only getting 3:1 on your money but the odds of hitting your hand at 4:1 are greater than the potential payoff at 3:1.
sorry if the above is confusing but a simple way of looking at this is supposed you have a 10 sided dice, and I tell you that i will roll the dice 10 times, and if i roll a 5, you have to pay me 9 dollars however if i roll anything other than a 5, i will pay you 1 dollar. statistically, with 10 rolls, i should hit the 5 10% of the time, or 9:1 odds. the payout will also be 9:1 or breakeven, meaning i will have paid you 9 dollars and you will have paid me 9 dollars after the conclusion of 10 rolls. now however, suppose i say, you pay me 10 dollars if i hit the 5, and i still only pay you 1 dollar for any other roll. now the payoff is 10:1 which is greater than the 9:1 odds of making my roll. at the end of 10 rolls, i should have $10 and you have $9. This makes the play profitable and plus EV in the long run.
of course the above only really works out in the long run, when you have put your money in with the best odds, you will be plus EV in the long run, however keep in mind, in the short term, suck outs will happen. with 10 rolls of the 10 sided dice, most likely you will not always get one of each value. however with 100,000 rolls of the dice, the distribution should fall more within the statistical norm.
i hope the above makes sense and should be relevant if poker dice has betting action, though the odds to hit the best hand could be different in poker dice vs traditional texas holdem, the same principles should hold true and that is to not only use probability to determine the next course of action, but the probability of winning the hand along with the pot odds to determine if you have the right odds to make a call or to see the next card given the betting action.
