NSTimer init problem

Discussion in 'iOS Programming' started by aukemid, Nov 20, 2010.

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  1. aukemid, Nov 20, 2010

    aukemid macrumors newbie

    Joined:
    Mar 26, 2010
    #1
    I have the following code to start a timer:
    Code:
    self.timer = [NSTimer scheduledTimerWithTimeInterval: (60 / 118)
			target: self
			selector: @selector(timerFiredMethod)
			userInfo: nil
			repeats: YES];
    This does not work!
    The result of 60 / 118 = 0.5084745763. If I enter this result as interval it does work. Can someone tell me why this is?
     
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  2. Luke Redpath, Nov 20, 2010

    Luke Redpath macrumors 6502a

    Joined:
    Nov 9, 2007
    Location:
    Colchester, UK
    #2
    If you divide two integers you will get an integer result.

    Try 60.0 / 180.0.
     
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  3. chown33, Nov 20, 2010

    chown33 macrumors 604

    Joined:
    Aug 9, 2009
    Location:
    Brobdingnag
    #3
    60 and 118 are integer constants. Therefore, their type is int, and all arithmetic will be performed with integer quantities. So calculated as an integer, 60/118 is 0.

    If you want fractional quantities, you must use numbers that have fractional parts, even if the fractional part is 0. A fractional constant is one containing a decimal point. Example: 60.0 / 118.0.

    The fractional types are 'double' and 'float'. Here, I use the word "fractional" to mean "capable of representing a fraction". Clearly, the integer types (char, int, long) do not have this capability, or they wouldn't be integer types.
     
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  4. aukemid, Nov 20, 2010

    aukemid thread starter macrumors newbie

    Joined:
    Mar 26, 2010
    #4
    Thanks, that solved it.
     
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