macOS Shell script to kill all background jobs

[l0uismustdie]

Hello, I've come up with a command which will list all the background processes running in my current shell and am trying to run it from a shell script but am experiencing some difficulty. The script looks as follows:

#! /bin/sh                                                                      
jobs -l | grep -o '[0-9]* ' | xargs -E eofstr kill -9

If I run this line directly in my terminal it works fine but if I try to execute from the script it doesn't seem to do anything.

Any ideas?

Thanks.

 

[willieva]

The jobs command shows the processes that have been started in the current shell. When you run it in a script it is in a new shell and not aware of the jobs in the parent shell.

 

[subsonix]

An alternative approach, create an alias instead of a script.

 

[l0uismustdie]

im not sure what you mean by 'create an alias'. And how could I use this to solve the problem. Thanks for responding!

 

[subsonix]

im not sure what you mean by 'create an alias'. And how could I use this to solve the problem. Thanks for responding!

As willieva mentioned, your script will run in a new shell. By creating an alias you can substitute the line you have with one identifier. Since this is just an alias, it will run in your current shell.

$ alias greetings='echo "hello"'
$ greetings
hello

 

[l0uismustdie]

Yep, awesome. Works great thanks guys.