Become a MacRumors Supporter for $50/year with no ads, ability to filter front page stories, and private forums.
Here's one, I'm sure many engineers/aspiring engineers arent too fond of it:
185ff6a342b3ec1719643396613151e2.png
98b1c5025462d42cfe3a9e9eb95a0afa.png
 
Here's a good one.

NASA uses this;

a6b64d4d7703a1d3bdefa9ab39dc4378.png
Universal gravitation. The Ug helped as well, but I recognized it anyway. I don't, however, remember the totally random value of G, though.

Mine is attached. fun! (I would have typed it or something, but I don't have such editors available to me at the moment)
 

Attachments

  • formula.jpg
    formula.jpg
    8.9 KB · Views: 77
Oooooh how difficult.
Pythagorean theorem for finding one of the shorter sides.

I might be mistaken but would finding the length of the shorter side (a) be:

c^2 - b^2 = a^2

The answer to my original equation (a^2 - b^2 = c^2) was how to find the foci (c) of an ellipse.

Edit: Corrected to reflect akonradi answer. thanks
 
Universal gravitation. The Ug helped as well, but I recognized it anyway. I don't, however, remember the totally random value of G, though.
That's kinda what I had… *headslap*

Mine is attached. fun! (I would have typed it or something, but I don't have such editors available to me at the moment)
2-proportion z-interval.

Here's mine:

1/2·π^2·r^4

I have another one but I'm not sure how well known it is. Plus I don't know if it has a name…
 
I might be mistaken but would finding the length of the shorter side (a) be:

c^2 - b^2 = a^2

The answer to my original equation (a^2 - b^2 = c^2) was how to find the foci (c) of an ellipse.

c^2 - b^2 = a^2

Hmm okay I was assuming that 'C' would be the side you are finding the length of, and not necessarily the hypotenuse.

I just knew that if it was a minus, it was the equation to find either of the shorter sides (as opposed to addition for the hypotenuse).
 
Register on MacRumors! This sidebar will go away, and you'll see fewer ads.