Actually, if you take a deep breath and read what I've wrote, you might find I've tried to help you refine your question and understand what precisely you are asking.
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Hi-rez displays on all devices
- Thread starter winterquilt
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Actually, if you take a deep breath and read what I've wrote, you might find I've tried to help you refine your question and understand what precisely you are asking.
It would seem to me, the OP has been very unclear until just the few recent posts as to what his goal, or what his actual question is. It took three days for him to say it but it seems like he wants to know if his macbook and projector resolution is beyond his limit of resolving two pixels from the distance that he normally views it.
If the limit is 1 arcminute, 0.0166667 degrees, or 2.91E-4 radians (rounded) then follow this:
theta = arcTan[L/(R*D)]
theta is the angle of viewing between pixels
L is the Length of the screen in that dimension
R is the number of pixels in that dimension
D is the distance away that you view it
This will have to be done for both the hiegth of the screen and the width becuase pixels are not always sqaure. If theta<1 arcminute, then your screen is better than the human eye can see and a higher resolution will not be noticed. If theta>1 arcminute then getting a higher resolution screen will be a better picture
If you need you hand held, multiply R and D first (R*D), then divide L by the product of R and D L/(R*D), then take the arcTan of the whole thing.
If that is not answering your question then you have yet to ask your question in a clear manner.
PS. I second Haathi....you've been a pr*ck.
If the limit is 1 arcminute, 0.0166667 degrees, or 2.91E-4 radians (rounded) then follow this:
theta = arcTan[L/(R*D)]
theta is the angle of viewing between pixels
L is the Length of the screen in that dimension
R is the number of pixels in that dimension
D is the distance away that you view it
This will have to be done for both the hiegth of the screen and the width becuase pixels are not always sqaure. If theta<1 arcminute, then your screen is better than the human eye can see and a higher resolution will not be noticed. If theta>1 arcminute then getting a higher resolution screen will be a better picture
If you need you hand held, multiply R and D first (R*D), then divide L by the product of R and D L/(R*D), then take the arcTan of the whole thing.
If that is not answering your question then you have yet to ask your question in a clear manner.
PS. I second Haathi....you've been a pr*ck.
I am sorry to dig this thread from the grave but this is important.
If you want to match the vision of normal, healthy person:
needed distance = 11459 divided by PPI
needed PPI = 11459 divided by distance from display
*11459 is derived from tangent of 0.3 arcminute angle.
If you want to match the vision of normal, healthy person:
needed distance = 11459 divided by PPI
needed PPI = 11459 divided by distance from display
*11459 is derived from tangent of 0.3 arcminute angle.
Now factor in display tech.
GNEX...AMOLED + Pentile + High PPI = still looks inferior to the iPhone 4S.
Less than a year later...
You got me there, i guess. I still wouldn't wait a year for an upgraded display if i needed a laptop, but I completely forget the context of my original post