I currently have a 3g iPod touch and trying to do the waiting game for an iPhone to surface on T-Mobile. However, with all these Verizon rumors blowing up, should I just get the new 4g iPod touch and enjoy what I can get?
You can already use an iPhone with a T-Mobile SIM...
Only if you jailbreak it and, in addition, unlock it. Which apparently can be an issue with some ROMs.
there are factory unlocked iphones on ebay. In Canada, you can buy an iphone directly from apple that is not locked to any carrier. Its worth looking into!
If it was someone who didn't care about its hardware, then yes, it will be worth it.This. If someone can ship the iphone from canada to you, it would be awesome. Its unlocked from apple so no need to jailbreak. It will be slightly expensive...but it will be worth it IMO.
there are factory unlocked iphones on ebay. In Canada, you can buy an iphone directly from apple that is not locked to any carrier. Its worth looking into!
If it was someone who didn't care about its hardware, then yes, it will be worth it.
I went to Ottawa to visit my grandparents for two weeks in August did have a chance in getting one at the Apple Store (they even allowed commitment-free customers to bypass the line). But with all the problems surfacing and the fact that it would run on EDGE on T-Mobile, there's no way I would buy any iPhone.
I suppose it's best to just wait it out since the new iPod Touch isn't worth the need to upgrade?
So, hang on, how would the iPhone being officially released on T-Mobile solve any of the so called "problems" or the fact that it would run on EDGE? If those are dealbreakers for you, why not just get the iPod Touch?
There would be some radio differences. I don't know whether they could solve it with some low level firmware differences, or if there are hardware changes required.
A reason that I don't think all the opening up of frequency bands is a panacea. How many phones could support 7, 8, etc, bands? Antenna changes would be required, and we already know that they can be a problem area![]()