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Assuming both use the same handles and all that changes is the degree, then a ratio is 1.3225806452, which would mean that at 120 degrees it is: ~90.73.171 foot pounds

Mind you this is a highly assumed estimate without know length of the bar of each.
 
If 82 degrees of rotation equals 62 foot pounds of force, how much force would 120 degrees of rotation equal?

Assuming both use the same handles and all that changes is the degree, then a ratio is 1.3225806452, which would mean that at 120 degrees it is: ~90.73.171 foot pounds

Mind you this is a highly assumed estimate without know length of the bar of each.
If the rate of generating foot pounds is consistent per degree of rotation, then I arrived at the same answer. 90.73 foot pounds, but maybe it’s not a 1 to 1 ratio? :)
 
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If 82 degrees of rotation equals 62 foot pounds of force, how much force would 120 degrees of rotation equal?

It doesn't work this way.

Too many variables as to the bolt size, coatings(oil or anti-seize), thread pitch etc. When you are using a rotational number, such as on automotive heads, a starting value is given in ft/lbs (usually a low number just enough to begin clamping), then you apply the rotational value. At this point it does not matter if the bolt is dry, rusty or lubricated, the clamping force will be the same.
 
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