Multiplying array elements by 3. C program on Xcode

On the last return line, I get the error:
Thread 1: Signal SIGABRT.

I have written the C program on xcode.
This is a program to multiply an array by 3 and return new values.
Please tell me what the error is and any suggestions to make this program work.

Learning C from 2 weeks.

#include <stdio.h>

int modify(int anth[10])
{
int i;
for(i=0;i<10;i++)
{
anth*=3;
}
return anth[10];
}

int main(int argc, const char * argv[])
{
int i, *anth;
int arr[10]={1,2,3,4,5,6,7,8,9,10};
anth=arr;
modify(&arr[10]);
for(i=0;i<=9;i++)
{
printf("%d.", arr);
}
return 0;
}

 

Thanks Lee!
1) I removed 10(overflow) within [] from modify() while defining the function.

2) while calling function modify. Used modify(arr) instead of modify(&arr[10])

And it worked perfect!

While returning values however, we need the [10]. Is it because we're indicating size of array being returned?