macOS Regular Expression for Find and Replace?

[davedev100]

How would I create a regular expression to find and replace all the functions declarations in an class file with a copy of the function declaration and then a call to object passing the function name for debugging purposes.

For example, I'd want to replace

function showSkittles(){

with

function showSkittles(){
debugObject.traceFunction("showSkittles");


Pseudo expression code would look like this:


Find ("<>" enclose variables):

"public function" + <function name> + "}"

Replace with:

<found string> + line break + "debugObject. traceFunction(" + <function name> + ");"

 

[Hansr]

Something like this?

"function\W*([^\(\W])\(\)\{\n"

"function $1(){\ndebugObject.traceFunction("$1");\n"

 

[gnasher729]

How would I create a regular expression to find and replace all the functions declarations in an class file with a copy of the function declaration and then a call to object passing the function name for debugging purposes.

For example, I'd want to replace

function showSkittles(){

with

function showSkittles(){
debugObject.traceFunction("showSkittles");

Don't do that. Look up in the compiler manuals what macros exist that evaluate to the function name. Like __func__ .

 

[davedev100]

gnasher729, thanks for the suggestion. I'm working in ActionScript so the function name is not available. You can get a reference to the function but not the function name.

----------

Hansr, thanks for the regex. Can you give a brief explanation? It fails after "function\W*" for me and I don't know enough to figure it out.

 

[Hansr]

Regex find and replace is implemented differently for each text editor/IDE but basically it's:


function <- the word function
\W* <- one or more whitespace characters
([^\(\W]) <- match anything not ( nor whitespace, e.g. function name
\(\) <- brackets ()
\{\n <- open curly brackets + linebreak

The replace works the same way but $1 will contain the match.

 

[jpyc7]

Hansr, thanks for the regex. Can you give a brief explanation? It fails after "function\W*" for me and I don't know enough to figure it out.

Based on Hansr's explanation, I would guess that the specification of whitespace characters is different for your regex processor.

Two other common ways of specifying a whitespace character are:
\S or \s
[:space:]

The latter is supposedly the POSIX standard, but sometimes you need extra square brackets on both sides because the regex processor treats square bracket characters specially too.