Solve This Maths Problem?

[impulse462]

In other words: You can compute the 0.7 (heavily rounded btw) without using ln by using another logarithmic base. I just used the term above
(log 2 / log e = 0.7) to make it clear that ln isn't needed.

I unfortunately had the problem explaining what I meant in English.

still a confusing post, but i get what you're saying

 

[mobilehaathi]

In other words: You can compute the 0.7 (heavily rounded btw) without using ln by using another logarithmic base. I just used the term above
(log 2 / log e = 0.7) to make it clear that ln isn't needed.

I unfortunately had the problem explaining what I meant in English.

I understand what you meant now, no worries.

 

[Veldek]

still a confusing post, but i get what you're saying

I understand what you meant now, no worries.

Thanks, I already became desperate