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Just called att and they told me they could give me 0102 as the last 4 digits but i already have 1717 hmmmmm
should i switch numbers to the 0102 number?
 
In Dallas-Fort Worth, they just added a new area code , the new area code is 469 LOL;)
 
I got 5959

One of my friends requested and received this one, but he now regrets it. I'll leave it up to anyone curious to figure out what it converts to. NSFW lol 277-3825

HAHAHA that's funny right there! Wow.
 
I know you said your name was Michael, but I believe the possibilities of randomly pressing 7 numbers and it being "Michael" is one in 2,097,152.

I say this because there are 8 possible digits you can press (1 and 0 don't have any letters), so that leaves out any phone numbers with 0 or 1. So I believe you just multiply the possibilities by the number of possibilities, so that is 8* 8* 8* 8* 8* 8* 8 or 8^7 power. Of course, I doubt anyone has a name of AAAAAAA. But whatever. Someone want to see if my math is right? I don't think there are other variables, right?

Actually the chances are 1:2,642,411,520. I took a Discrete Mathematics class and we actually worked with problems like this. You also have to take into account the order of the letters and corresponding numbers which has to be exact and then the fact that both H and I are on the same number and C and A are on the same number increasing your chances by a factor of 4.

Oh and the last 4 of mine are 6347. Used to be 396-6347, but I moved and kept the last 4 digits. Used to have 6969 many years ago before Cingular was AT&T when I had Centennial.
 
I had one back when I had Rogers PayGo, my birthday 0731.


Now, nothing. 4607.
 
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