Maybe Tom (aka: Doctor Q) also created Caffeine, zoso98765, & chrberni. Considering none of them ever made a single post.angelneo said:Dr Q, did you sign up that account by yourself? I smell conspiracy....
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Welcome Tom!
- Thread starter Doctor Q
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It's especially cool that the thread number of this thread happens to be a power of two.
I'm guessing that even the amazing emw will need a moment to think about that claim.
(By the way, this is the most pointless thread ever. I read that somewhere on the Internet so it must be true.)
I'm guessing that even the amazing emw will need a moment to think about that claim.
(By the way, this is the most pointless thread ever. I read that somewhere on the Internet so it must be true.)
EricNau said:
I doubt Tom created them because if you just type in random id's, you would notice that most users (at least in my sample) have 0 posts.
Unless you left out some digits, that doesn't equal 174905, it's still a little off. (174,904.999999837)
No, because then I'd think you were talking to me.emw said:
Heck, I thought this thread was about me. I DEMAND MY THREAD!
65536
Using only exponentiation, multiplication, and grouping:
2^(2^(2x2)) = 65536
2^((2x2)^2) = 65536
2^(2^(2^2)) = 65536
2^((2^2)^2) = 65536
(2x2)^(2x2x2) = 65536
(2^(2x2x2))^2 = 65536
(2^2)^(2x2x2) = 65536
(2^((2^2)x2))^2 = 65536
(2^2)^(2x(2^2)) = 65536
and lots more!
Not to mention that this marks the grand expansion of MacRumors into member numbers not representable in an unsigned word of memory!!
Using only exponentiation, multiplication, and grouping:
2^(2^(2x2)) = 65536
2^((2x2)^2) = 65536
2^(2^(2^2)) = 65536
2^((2^2)^2) = 65536
(2x2)^(2x2x2) = 65536
(2^(2x2x2))^2 = 65536
(2^2)^(2x2x2) = 65536
(2^((2^2)x2))^2 = 65536
(2^2)^(2x(2^2)) = 65536
and lots more!
Not to mention that this marks the grand expansion of MacRumors into member numbers not representable in an unsigned word of memory!!
Grrrrrrrr! I was keeping an eye on the odometer on one of our cars as it approached 65,536 miles, but I missed it! I was gonna take a photo as a keepsake of the big moment, but I didn't catch it until 65,537! It's a big disappointment.
If I drive backwards a mile, will it roll back?
If I drive backwards a mile, will it roll back?
So far there are a whopping 12 posts from the 2^x user base. (assuming you don't count 2^0 = arn)
2^1 = chrberni
2^2 = no user
2^3 = no user
2^4 = burinato
2^5 = rinse
2^6 = Lonejawa
2^7 = dbarb
2^8 = Fukker
2^9 = bert
2^10 = Pedro
2^11 = adamluc has 5 posts
2^12 = prjibaro
2^13 = varta123 has 7 posts
2^14 = Caffeine
2^15 = zoso98765
2^16 = tomrom1@mac.com
2^1 = chrberni
2^2 = no user
2^3 = no user
2^4 = burinato
2^5 = rinse
2^6 = Lonejawa
2^7 = dbarb
2^8 = Fukker
2^9 = bert
2^10 = Pedro
2^11 = adamluc has 5 posts
2^12 = prjibaro
2^13 = varta123 has 7 posts
2^14 = Caffeine
2^15 = zoso98765
2^16 = tomrom1@mac.com
Nice summary, atszyman. Perhaps there is a curse of the 2-powers, preventing them from speaking. And it can only be broken by lucky number 2^13. But that wouldn't explain posts by 2^11.
So I have a simpler and more likely explanation. Let L = log base 2 (member number). If L is an integer, that member posts if and only if L and L-6 are both prime.
1 = 2^0: 0 and -6 not both prime
2 = 2^1: 1 and -5 not both prime
4 = 2^2: 2 and -4 not both prime
8 = 2^3: 3 and -3 not both prime
16 = 2^4: 4 and -2 not both prime
32 = 2^5: 5 and -1 not both prime
64 = 2^6: 6 and 0 not both prime
128 = 2^7: 7 and 1 not both prime
256 = 2^8: 8 and 2 not both prime
512 = 2^9: 9 and 3 not both prime
1024 = 2^10: 10 and 4 not both prime
2048 = 2^11: 11 and 5 are both prime
4096 = 2^12: 12 and 6 not both prime
8192 = 2^13: 13 and 7 are both prime
16384 = 2^14: 14 and 8 not both prime
32768 = 2^15: 15 and 9 not both prime
65536 = 2^16: 16 and 10 not both prime
131072 = 2^17: 17 and 11 are both prime
Therefore, member #131,072 will be a talkative one.
So I have a simpler and more likely explanation. Let L = log base 2 (member number). If L is an integer, that member posts if and only if L and L-6 are both prime.
1 = 2^0: 0 and -6 not both prime
2 = 2^1: 1 and -5 not both prime
4 = 2^2: 2 and -4 not both prime
8 = 2^3: 3 and -3 not both prime
16 = 2^4: 4 and -2 not both prime
32 = 2^5: 5 and -1 not both prime
64 = 2^6: 6 and 0 not both prime
128 = 2^7: 7 and 1 not both prime
256 = 2^8: 8 and 2 not both prime
512 = 2^9: 9 and 3 not both prime
1024 = 2^10: 10 and 4 not both prime
2048 = 2^11: 11 and 5 are both prime
4096 = 2^12: 12 and 6 not both prime
8192 = 2^13: 13 and 7 are both prime
16384 = 2^14: 14 and 8 not both prime
32768 = 2^15: 15 and 9 not both prime
65536 = 2^16: 16 and 10 not both prime
131072 = 2^17: 17 and 11 are both prime
Therefore, member #131,072 will be a talkative one.
A totally geeky, and slightly unrelated fact: tomrom is also Norwegian for void (as in empty space, but still).
I'm such a geek...
I'm such a geek...
Doctor Q said:
Not extremely talkative. Your pattern also holds that they will post only L-6 times.... so user #131072 will have 11 posts before being silenced...
I wonder if he's read A Void, a translation by Gilbert Adair of the amazing book La Disparation by Georges Perec. I bought A Void because of its geeky in-joke, not for its detective story. It might be fun to try to spot the in-joke while reading it, but that's hard to do since book reviews usually give it away.Mitthrawnuruodo said:
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I'd like to belatedly welcome member shklogan1 (member 2^17=131072), who made one post about iPhones back in 2007, in keeping with my theory above about which power-of-two members would post and which would not.
I'd like to more promptly welcome member packerfan43042 (member 2^18=262144), who joined Saturday and has yet to post about football in Wisconsin or anything else.
In case you were wondering, 43042 is twice the prime number 21521.
I'd like to more promptly welcome member packerfan43042 (member 2^18=262144), who joined Saturday and has yet to post about football in Wisconsin or anything else.
In case you were wondering, 43042 is twice the prime number 21521.