I actually did take the time to read this post, and it is something I am quite knowledgeable of.
What you say is basically right but extremely superficial and doesn't say anything about what is really happening. It is the internal resistance of the battery that limits the about of power the battery can output "C" in this case. It is a simple matter of Ohm's Law (Voltage = Current times Resistance) where in this case the resistance is basically the sum of the battery's internal resistance and the load (the power draw of the iPhone).
For any given current draw, part of the voltage will drop across the load and part will drop across the battery in direct proportion to the resistances (this is Kirchoff's voltage law). So, when the internal resistance of the battery is near zero, most of the voltage drops across (is supplied to) the device. When the internal resistance of the battery is higher, a larger proportion of the voltage drops across the battery and the device sees a lower voltage being provided to it.
You can see from Ohm's law that the higher the current, the higher the voltage drop for a given resistance, so the higher the current the more voltage drops across the battery and the lest voltage is supplied to the device. When the voltage to the device gets low enough, the device doesn't work any more and in the case of an iPhone, you have your shutdown.
This concept of "C" you're talking about is not any intrinsic property of the battery but a very, very rough guess that the battery has a low enough internal resistance to supply that much current without the voltage dropping too much.
Now back to the iPhone specifically. The internal resistance is affected by a lot of factors, the particular chemistry and the surface area of the electrodes (limited by the size and shape of the battery) being major ones. Internal resistance also goes up as the battery ages.
The battery int the iPhone 6 an later is too small to provide a enough power the phone. The small size means the internal resistance is too high and it is unable to provide a sufficient voltage at sufficient current. When the battery is brand new, it can sort of do the job, but even slightly aged (slightly higher internal resistance) means too much voltage drops across the battery.
A physically larger battery with larger electrode area and lower internal resistance would have solved all of these issues.
now, tl;dr....Apple chose the wrong battery for their iPhones and every iPhone since the 6 is defective by design.
Of course my post is simple. I have to consider that not everyone reading is an engineer.
Strongly disagree that the iPhone 6 battery (or later batteries) are defective by design. You have literally zero proof of this.
A few people online with throttled devices doesn’t mean the design is defective. The only way you could come to that conclusion is if you know the total number of devices in use and what percentage of them are functioning normally and what percentage are being throttled due to defective batteries. Since you don’t have this data, your conclusion that the batteries are “defective by design” is nothing more than a fabrication.